WebFocal chord to y 2=16 x is tangent to x 62+ y 2=2 then the possible values of the slopes of this chords,areA. 1,1B. 2,2C. 2, 1/2D. 2, 1/2 Question Focal chord to y 2 = 16 x i s t a n g e n t t o ( x − 6 ) 2 + y 2 = 2 then the possible values of the slopes of this chord(s),are WebMay 6, 2016 · Question: Prove that the directrix is tangent to the circles that are drawn on a focal chord of a parabola as diameter. ... Prove that in a parabola the tangent at one end of a focal chord is parallel to the normal at the other end. 0.
Find the equation of the tangent to the Parabola y^2=5x , that is ...
WebThe focal chord to y2 = 16x is tangent to (x – 6)2 + y2 = 2, then the possible values of the slope of this chord, are (2003S)a){–1, 1}b){–2, 2}c){–2, –1/2}d){2, –1/2}Correct answer is option 'A'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE ... WebThe focal chord to y2 =64x is tangent to (x−4)2+(y−2)2 =4 then the possible values of the slope of this chord is Q. The focal chord to y2 =16x is tangent to (x−6)2+y2 =2, then the possible value of the slope of this chord are Q. The focal chord to y2 =16x is tangent to (x−6)2+y2 =2, then slope of focal chord is Q. phim the vvitch
Focal chord to y2=16x is tangent to x−62+y2=2 then the
WebDec 1, 2024 · Focal chord of the parabola is tangent to the circle (x−6)^2+y^2=2. 2and (6,0) are radius and centre of the circle As radius is perpendicular to the tangent, we have length of tangent from (4,0) to the circle is = 2 . From the diagram, we have tan teta= 2/ 2=1⇒θ=45 Therefore, slope of the chord is ±1= (−1,1). Advertisement Answer WebAny chord through focus is called a focal chord and any chord perpendicular to ... 9 3 x 2 y2 Ex.2 Find the equation of the straight lines joining the foci of the ellipse 1 to the 25 16 x 2 y2 foci of the ... parallel to the line y + 2x = 4. Ex.2 Equation of the tangent to an ellipse 9x2 + 16y2 = 144 passing from (2, 3). ... WebSOLUTION. Here, the focal chord of y2 =16x is tangent to circle (x−6)2+y2 = 2. ⇒ Focus of parabola as (a,0) i.e. (4,0) Now, tangents are drawn from (4,0) to (x−6)2+y2 = 2. Since, P … phim the voice season 1